(1x-6)(1x^2-4x+2)=

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Solution for (1x-6)(1x^2-4x+2)= equation: 


Simplifying
(1x + -6)(1x2 + -4x + 2) = 0

Reorder the terms:
(-6 + 1x)(1x2 + -4x + 2) = 0

Reorder the terms:
(-6 + 1x)(2 + -4x + 1x2) = 0

Multiply (-6 + 1x) * (2 + -4x + 1x2)
(-6(2 + -4x + 1x2) + 1x * (2 + -4x + 1x2)) = 0
((2 * -6 + -4x * -6 + 1x2 * -6) + 1x * (2 + -4x + 1x2)) = 0
((-12 + 24x + -6x2) + 1x * (2 + -4x + 1x2)) = 0
(-12 + 24x + -6x2 + (2 * 1x + -4x * 1x + 1x2 * 1x)) = 0
(-12 + 24x + -6x2 + (2x + -4x2 + 1x3)) = 0

Reorder the terms:
(-12 + 24x + 2x + -6x2 + -4x2 + 1x3) = 0

Combine like terms: 24x + 2x = 26x
(-12 + 26x + -6x2 + -4x2 + 1x3) = 0

Combine like terms: -6x2 + -4x2 = -10x2
(-12 + 26x + -10x2 + 1x3) = 0

Solving
-12 + 26x + -10x2 + 1x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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